<PRE><B>Question 1173331</B>
.
&lt;pre&gt;

Let consider section A.


There are &amp;nbsp;5 &amp;nbsp;male and &amp;nbsp;6 &amp;nbsp;female there.


You can form  &amp;nbsp;&amp;nbsp;5 * 6 = 30 &amp;nbsp;&amp;nbsp;different pairs of them.
&lt;/pre&gt;

Solve &amp;nbsp;&lt;U&gt;similarly&lt;/U&gt; &amp;nbsp;for two other sections  &amp;nbsp;B &amp;nbsp;and &amp;nbsp;C &amp;nbsp;on your own &amp;nbsp;&lt;U&gt;in  the same way&lt;/U&gt;.




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