Question 1173309
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Since the lead coefficient is negative, the graph of the quadratic function is a concave down parabola.  Since the value of the function is the height at time *[tex \Large t], the value of the function at the vertex is the maximum height attained by the diver.  The value of the independent variable in *[tex \Large y(t)\ =\ at^2\ +\ bt\ +\ c] at the vertex is *[tex \Large -\frac{b}{2a}].  The value of the function at that point is *[tex \Large y\(-\frac{b}{2a}\)].  You can do your own arithmetic.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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