Question 1173284
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Hi  
four consecutive even integers: n , (n+2), (n+4), (n+6)
three times the sum of the first and third numbers 
is equal to four times the sum of the second and fourth numbers. 
3(n + (n+4)) = 4((n+2) + (n+6))
3(2n+4) = 4(2n+8)
6n + 12 = 8n + 32
 -20 = 2n
n = -10
four consecutive even integers are:  -10, -8, -6, -4 
Checking our Answer:
3(-16) = 4(-12) = 48  checks!
Wish You the Best in your Studies.

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