Question 1173273
Find four consecutive even integers...
<pre>
the first number, the smallest, even integer = x

the second number, the next to smallest, even integer = x+2

the third number, the next to largest, even integer = x+4

the fourth number, the largest even integer = x+6

the sum of the first and third numbers = x+(x+4) = x+x+4 = 2x+4 

the sum of the second and fourth numbers. (x+2)+(x+6) = x+2+x+6 = 2x+8 
</pre>...three times the sum of the first and third numbers is equal to 
four times the sum of the second and fourth numbers.<pre>

3(2x+4) = 4(2x+8)
  6x+12 = 8x+32
    -2x = 20
      x = -10

So,

he first number, the smallest, even integer = -10

the second number, the next to smallest, even integer = -8

the third number, the next to largest, even integer = -6

the fourth number, the largest even integer = -4

Answer: 10, -8, -6, -4.

Checking: 

the sum of the first and third numbers = (-10)+(-6) = -16 
 
the sum of the second and fourth numbers = (-8)+(-4) = -12

It's true that 3 times -16 which is -48, is equal 
to 4 times -12, which is also -48.

Edwin</pre>