Question 1173191
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The maximum amount  {{{d[max]}}}  is the sum of the infinite Geom. progression 

with the first term  "a" = 80 milligrams  and the common ratio  r = 0.5^(24/22) = 0.469465


     {{{d[max]}}} = {{{a/(1-r)}}} = {{{80/(1-0.469465)}}} = 150.7913  milligrams.


The minimum amount  {{{d[min]}}}  is 80 milligrams less than {{{d[max]}}}, i.e  {{{d[min]}}} = 70.7913  milligrams.


As the time becomes very large, the process (the plot of the function d(t)) is periodical with the period of time equal to 24 hours.
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Solved, answered and explained.