Question 1173199
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<pre>

You start with

    x^2 - 4x - 6 = 0


The term  "-4x "  says you that the expected square term should be {x-2)^2 = x^2 - 4x + 4


So we add 10 to both sides

    x^2 - 4x + 10 - 6 = 10,   or

    x^2 - 4x + 4 = 10.


In the left side you just have the desired square:

    {x - 2)^2 = 10.


Now take the square root from both sides

    x - 2 = +/- {{{sqrt(10)}}}


Your last step is to move -2 from the left side to the right, changing the sign

    x = 2 +/- {{{sqrt(10)}}}.


The problem is just solved.


<U>ANSWER</U>.  The given equation has two roots  x = 2 + {{{sqrt(10)}}}  and  x = 2 - {{{sqrt(10)}}}.
</pre>


So, &nbsp;we solved the equation by completing the square method.


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