Question 1173185
A dog trainer has 88 ft of fencing that will be used to create a rectangular work area for dogs.
2L + 2w = 88
simplify, divide by 2
L + w = 44
L = (44-w), use this form for substitution
:
 If the trainer wants to enclose an area of 420 ft2, what will be the dimensions of the work area?
L * w = 420
replace L with (44-w)
(44-w)*w = 420
arrange as a quadratic equation
-w^2 + 44w - 420 = 0
multiply by -1
w^2 - 44w + 420 = 0
this will factor to
(w-14)(w-30) = 0
two solutions
w = 14, then 44-14 = 30 is the length
and
w = 30, then 44-30 = 14 is the width
:
Check this:
 30 * 14 = 420
and
2(30) + 2(14) = 88
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