Question 1173186
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Hi  
The height of a triangle is 2 m more than twice the length of the base (x)
b is x 
h is (2x+2)
A = (1/2)b*h
30m^2 = (1/2)x(2x+2)
60 = 2x^2 + 2x
2x^2 + 2x - 60 = 0
Solve with the Pythagorean Theorem
Tossing out negative solution for length
{{{x = (-2 + sqrt(4+480))/(4) = (-2 + 22)4 = 5}}}  
x = 5m , the length
h =  (2x+2) = 12m
checking our Answer:
(5m)(12m) = 60m^2  Checks!
Wish You the Best in your Studies.