<PRE><B>Question 109206</B>
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{{{sqrt(8 - x - 6) = 4}}}
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{{{sqrt(2 - x) = 4}}}
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Square both sides:
2 - x = 4^2
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2 - x = 16
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-x = 16 - 2
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-x = 14
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We always want our unknown (x) to be positive, multiply equation by -1
x = -14
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Check solution in original equation:
{{{sqrt(8 - (-14) - 6) = 4}}}
{{{sqrt(8 + 14 - 6) = 4}}}; minus a minus is a plus
{{{sqrt(16) = 4}}}
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Did this help you?
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Next time you can write it Sqrt(8 - x - 6) = 4; brackets make it clear
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