Question 109490
(4p-4)/p * 8p^2/(9p-9)

= [4(p-1)/p]*[8p^2/9(p-1)]

Cancel factors common to a numerator and denominator, such as p,p-1, to get:

= [4/1]*[8p/9]

= 32p/9
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You are correct.
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Cheers,
Stan H.