Question 1173069
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Hi, 

3x^2+2x+5=0
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
 {{{x = (-2 +- sqrt( 2^2-4*3*5 ))/(2*3) }}}

 {{{x = (-2 +- sqrt( -56))/(6) }}}
 {{{x = (-2 +- sqrt( -1*4*14))/(6) }}} 
 {{{x = (-2 +- 2isqrt(14))/(6) }}}       | √-1  = i 
 x = {{{-1/3 +- (i/3)sqrt(14 )}}} 
 Wish You the Best in your Studies.