Question 1173041
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Hi
Previously Posted
(1+cotx)/(1-cotx)=(sinx+cosx)/(sinx-cosx)
(1+cotx)/(1-cotx) = {{{(1+1/tanx)/(1-1/tanx)}}}
{{{(1+1/tanx)/(1-1/tanx) =( tanx + 1)/(tans -1) }}}
{{{( tanx + 1)/(tans -1)= ((sinx/cosx) + 1)/ ((sinx/cosx) - 1) }}}
{{{((sinx/cosx) + 1)/ ((sinx/cosx) - 1) =(sinx+cosx)/(sinx-cosx)   }}}
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