Question 1172914
.
water in a hemispherical bowl with a diameter of 30 cm begins to pour out when the bowl is tilted 
to an angle of theta equal to 22 degrees how deep is the water in the bowl.
~~~~~~~~~~~~~~~~~



Look at the figure in this link


https://socratic.org/questions/the-water-level-in-a-hemispherical-bowl-of-radius-12-inches-is-4-6-inches-what-a



From this figure,  the surface of the water in the hemispherical bowl will be 



               15*sin(22°) = 15*0.374 = 5.62 cm     below horizontal level of the edge of the bowl  (rounded).



Hence, &nbsp;the depth of the water in the bowl will be  &nbsp;&nbsp;15 cm - 5.62 cm = 9.38 cm. &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U>
</pre>

------------


Solved and answered.



It is good entertainment problem, which I never saw before . . .