Question 109414
It is given that the area of the rectangle is {{{2(3x - 2)/(x - 1) }}}


the length is = {{{(2x + 6)/(12x - 15)}}} 


We are supposed to find the width of the rectangle.


We know that the area of the rectangle is given by A = l * w 


So substituing for the values, we get:


{{{2(3x - 2)/(x - 1) = (2x + 6)/(12x - 15) * w }}} 


therfore w = A/l 


w = {{{ (2(3x - 2)/(x - 1))/ ((2x + 6)/(12x - 15)) }}} 



Therfore w = {{{(2(3x - 2)/(x - 1)) * ((12x - 15)/(2x + 6)) }}}



This can be written as: 


w =  3((3x - 2)(4x - 5))/((x - 1)(x + 3))}}} 


Thus the solution.