Question 1172864
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Hi  
How many possible zeros of the given equation x^4- 2x^3 - 8x^2 +12x + 16 = 0?
4th Degree Equation:  d) 4 possible solutions. 
Solving or Using a Solver... the result would be 2 real and 2 imaginary roots

What are the possible zeros of the equation x^4 - 2x^3 - 3x^2 + 4x + 4 = 0
a.) ( x - 2)^2 ( x +1 )^2
Multiply:
(x^2 - 4x + 4)
<u>(x^2 +2x + 1)</u> = x^4 - 2x^3 - 3x^2 + 4x + 4
Or one can verify with an online 4th Degree Equation Solver
Wish You the Best in your Studies.