Question 1172854
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Hi  
Using exponents:
{{{1/11 = (11)^-1}}},  {{{3/c = 3c^-1}}}, {{{2a^3/b^2 = 2a^3b^-2}}}
15,600,000 = 1.56 x10^7  
(need to move 7 places up to the right of the period to complete the number)

 0.00000526 = 5.26 x10^-6  
(need to move 6 places back to the left of the period to complete the number.
Wish You the Best in your Studies.