Question 1172834
We can use systems of equations!
We can keep the variables on the right side of the equation, while keeping the constants on the right:
So 3x + y - 2 = 0 becomes 3x + y = 2 
So 2x - y - 3 = 0 becomes 2x - y = 3 
Now we can use systems of equations:
 3x + y = 2 
+ (2x - y = 3)
-----------------
3x+2x + y-y = 2+3
5x + 0 = 5
x = 1
Since we know what one of the variables equal, we can plug in the value of x in one (or both) of our equations.
3(1)+y = 2
y = 2-3
y = -1
Let's check if it works for our other equation as well!
2(1)-y = 3
2-y=3
-y = 3-2
-y = 1
y = -1
So, the answer to our problem is:
x = 1
y = -1
Also could be written as (x,y) -> (1, -1)