Question 1172791
A store is selling 100 notebooks. 36 yellow notebooks, 42 blue notebooks and 22 red notebooks. A customer buys one notebook. 
A second customer, buys a notebook too. What is the probability that the second customer would buy? :
1. A yellow notebook?
2. A red notebook?
3. A blue notebook if the first customer bought yellow notebook?
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            In this problem,  ALL  THE  DATA  are in place to solve it.



<pre>
(1)  P(2nd buys yellow) = P(1st buys yellow, 2nd buys yellow) + P(1st buys blue, 2nd buys yellow) + P(1st buys red, 2nd buys yellow) = 


                        =      {{{(36/100)*(35/100)}}}                  +    {{{(42/100)*(36/100)}}}                  +   {{{(22/100)*(36/100)}}} = 


                        =      {{{(36*35 + 42*36 + 22*36)/10000}}} = {{{3564/10000}}} = 0.3564.       <U>ANSWER</U>
</pre>


So, I answered question 1.




If you do understand the logic of my solution &nbsp;(which is crystally clear), 


you should be able to solve/answer question &nbsp;2 &nbsp;&nbsp;<U>ON &nbsp;YOUR &nbsp;OWN</U>, &nbsp;&nbsp;using &nbsp;THE &nbsp;SAME &nbsp;LOGIC.