Question 1172792
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Hi 
 Binomial Distribution
p(def) = .10 and n = 400
Using Calculator:
(a) 65 or more bolts are defective
P(x ≥ 65) = 1  -  P(x ≤ 64) = 1 - binomcdf(400,.1,64) = 1 - .9999 = .0001
(b) less than 35 bolts are defective
P(x< 35) = binomcdf(400,.1,34) = .1804
(c) At least 30 bolts are defective
P(x ≥ 30) = 1  -  P(x ≤ 29) = 1 - binomcdf(400,.1,29) = 1 - .0357 = .9643
(d) At most 60 bolts are defective
P(x ≤ 60) = binomcdf(400,.1,60) = .9994
(e) Between 40 and 60 bolts are defective
P(x ≤ 40) = .542
P = .9994 - .542 = 
P =  .9994 - .542 = .4574
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