Question 1172701
How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines)
:
We can find the height. A right triangle is formed, using sin(41), hypotenuse = 120 and side opposite is h, 
so we have: sin(41) = {{{h/120}}}
h = 78.7271
A = {{{1/2}}}b*h, where b=200 and h=78.73
A = {{{1/2}}}*200*78.7271
A = 7872.7 sq/units