Question 1172541
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The graph of your profit function is a concave down parabola, so the maximum profit is at the vertex of the parabola. The general equation for a parabola is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ax^2\ +\ bx\ + c]


The value of the independent variable at the vertex of the general parabola is *[tex \Large -\frac{b}{2a}].


Determine, by inspection, the values of *[tex \Large a] and *[tex \Large b] that are specific to your question and then calculate *[tex \Large x\ =\ -\frac{b}{2a}] to find your answer.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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