Question 1172491
This is a Poisson with parameter 1.1, 220/200
Look at p(0) and p(1), and subtract that from 1 to get the answer of p(>=2)
for p(0) it is e^(-1)*1.1^0/0!=0.33287 NOTE that value of e^(-1.1), NOT 0.033287.  It is 1/e^(1.1)
Also, given a parameter about 1, the probability of 0 should be very high.
p(1)=e^(-1.1)*1.1^1/1!=0.36616
That sum is 0.699
So the answer is 1-0.699=0.301.