Question 1172457
A student throws a ball vertically up with a speed of 33 m/s.
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Using g = 9.8 m/sec/sec for gravity:
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a.) How high will the ball rise before it goes down?
That's the max height.
It's the vertex of the parabola of h(t) = -gt^2/2 + 33t ---- t in seconds
h(t) = -4.9t^2 + 33t
Vertex is t = -b/2a = -33/-9.8
Max height = h(33/9.8) meters
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b.) How long will the ball stay in air before landing back to his hand?
Time ascending = time descending
= 2*(33/9.8)
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If you meant to use 10 m/sec/sec for gravity to make it easier, you have to specify that.