Question 1171881
<pre>
The cosine is negative in QII and QIII
The tangent is positive in QI and QIII

So the angle &theta; is in QIII

The angle &theta; is indicated by the red curved line swinging counter-clockwise 
around from the right side of the x-axis to the terminal side in QIII.
We draw the terminal side (in blue) of &theta; in QIII

Cosine is adjacent/hypotenuse = x/r, so we label x = adjacent = -15 (negative
because it goes left).

The value of y must be calculated by the Pythagorean theorem.

{{{r^2=x^2+y^2}}}
{{{17^2=(-15)^2+y^2}}}
{{{289=225+y^2}}}
{{{64=y^2}}}
{{{"" +- sqrt(64)=y}}}
{{{"" +- 8=y}}}
{{{-8=y}}}

We choose negative because y goes down from the x-axis.

{{{drawing(600,600,-18,18,-18,18,graph(600,600,-18,18,-18,18),
red(arc(0, 0,9,-9,0,209)), locate(-10,1.3,x=-15), locate(-18,-4,y=-8),
blue(line(0,0,-15,-8)), green(line(-15,0,-15,-8)),locate(-8.7,-4.5,r=17) )}}}
 
Sorry I can't "Check ALL of the statements below that are true" since you
didn't give any "statements below" and I wasn't able to read your mind. lol.

Edwin</pre>