Question 1172361
{{{y^2-8x-6y-23=0}}}

{{{y^2-6y=8x+23}}}

complete the square,  {{{y^2-6y+9=8x-23+9}}}

{{{(y-3)^2=8x-14}}}

{{{(y-3)^2=8(x-14/8)}}}

{{{(y-3)^2=8(x-7/4)}}}

{{{highlight_green((y-3)^2=8(x-1&3/4))}}}


Vertex at ( {{{1&3/4}}},3 ), and focus ( {{{4&1/4}}}, 3 ).











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