Question 1172326
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The tutor Boreal has the right idea, but we're dealing with a right-tailed test since we're asking the question "is the population proportion p greater than 2 percent?", where p is the population proportion of defective burners.


We have these hypotheses
H0: p = 0.02
H1: p > 0.02
The claim is made in the alternative hypothesis.


The test statistic z = 1.43 leads to a p value of roughly 0.0764; use a table or calculator to compute this.
This means P(Z > 1.43) = 0.0764 approximately.


At level of significance (los) 5%, aka alpha = 0.05, we fail to reject the null. 
We only reject the null if the p value is smaller than alpha.


The conclusion is the same as what Boreal got: There is insufficient evidence to conclude that the manufacturing process is turning out more than 2% defective burners.
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