Question 1172290
<pre>
Here's what you're supposed to do. For this problem you aren't supposed to do
any calculations at all.  You are to start by drawing the special 30-60-90
right triangle that you should memorize.  Learn how it looks when it's standing
up or when it's lying down.  Learn the sides. The shortest side (leg) is 1, the
middle size side (leg) is √3 and the longest (the hypotenuse) is 2.  The
smallest angle is 30°, the middle-sized angle is 60° and the right angle is, of
course, 90°. 

{{{drawing(200,115,-10,5,-2,7,
locate(-6.5,0,1),locate(-4.9,2.69,sqrt(3)),locate(-7.3,3,2),
triangle(-8,0,-5,0,-5,3sqrt(3)),locate(-.2,3,2),
locate(0,-.05,sqrt(3)),locate(2.3,1.8,1),
triangle(-3,0,-3+3sqrt(3),0,-3+3sqrt(3),3) )}}}

Then since your problem says a 30-60-90 triangle has a hypotenuse of 10,
instead of the sides being 

{{{matrix(1,5,shortest,side,(leg),""="",1)}}}, 
{{{matrix(1,5,medium,side,(leg),""="",sqrt(3))}}},
{{{matrix(1,5,longest,side,(hypotenuse),""="",2)}}},

as they are for the standard 30-60-90 right triangle,

since 10 is the hypotenuse, you just multiply all three sides
by 5 and get:

{{{matrix(1,5,shortest,side,(leg),""="",5)}}}, 
{{{matrix(1,5,medium,side,(leg),""="",5sqrt(3))}}},
{{{matrix(1,5,longest,side,(hypotenuse),""="",10)}}}

Edwin</pre>