Question 1172239
<br>
x = amount invested at 8%
100000-x = amount invested at 11%<br>
The total interest is 10100:<br>
{{{.08(x)+.11(100000-x) = 10100}}}<br>
Solve using basic algebra....<br>
Doing the above is a good exercise in solving problems using formal algebra.<br>
For a quick and easy way to answer a "mixture" problem like this, you can do this:<br>
(1) The 100,000 all invested at 8% would earn 8000 interest; all at 11% would earn 11,000 interest; the actual interest is 10,100.
(2) View the three numbers on a number line and use simple calculations to determine that 10,100 is 7/10 of the way from 8000 to 11,000.
(3) That means 7/10 of the total 100,000 was invested at the higher rate.<br>
ANSWER: 7/10 of the total 100,000, or 70,000 was invested at 11%; the other 30,000 at 8%.<br>
CHECK: .11(70,000)+.08(30,000) = 7700+2400 = 10,100<br>