Question 1172079
Draw this with 
=====C====

B-------------A
sin B=0.9111
sin A=0.8141

From these side b (AC) is by the Law of Sines 132.18 ft
side a (BC) is 118.11 ft.
Now draw a perpendicular from C to AB, reaching at point D.
This creates two right triangles, ADC and BDC.
Again by the Law of Sines (easier with a 90 degree angle as one of them and using the original angles again), CD, the distance across the river, is 107.61 feet.