Question 1172075
no sign change in f(x) so no positive zeros
one sign change in f(-x) so one negative zero.
factoring the function into x^2(x^3+8), there is a zero at -2 and a bounce at the origin.
Translating it up 1 unit will remove the bounce and shift the zero but not remove it
There is one negative zero.



{{{graph(300,300,-10,10,-10,10,(1/3)(x^5+8x^2)+1)}}}