Question 1172192
<br>
Not a good example of this kind of problem, since the given information makes a solution by logical reasoning easy....<br>
The 3 hours to stencil a small box and the 6 hours to stencil a large box, along with the total 30 hours available, makes the maximum possible number of boxes 30/3 = 10, so the condition that the number of boxes must be no more than 11 is superfluous.<br>
Then, since the time for stenciling a large box is twice the time for stenciling a small box, whereas the profit from a large box is LESS THAN twice the profit from a small box, makes it obvious that the maximum profit is by stenciling only small boxes.<br>
ANSWER: The maximum profit is by stenciling 30/3 = 10 small boxes (and 0 large boxes).<br>