Question 1172177
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Saw an error in tutor Cromlix' answer, so came in to show the fix:<br>

The expression should be:
{{{ x^2 - (2x + 3) = 0 }}}, leading to... <br>

{{{ x^2 - 2x - 3 = 0 }}}
{{{ (x-3)(x+1) = 0 }}}<br>

x=3  and/or x=-1

Keeping just the positive answer, {{{ highlight( x=3 ) }}}

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Tutor Cromlix tried to fix his answer, and while he arrives at the correct answer of x=3 this time, his steps still contain several errors:

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Hi there,
Making x the positive number
x^2 - 3 + 2x = 0          <<< should be  x^2 - 3 - 2x = 0
Rearrange
x^2 - (2x - 3) = 0 
x^2 - 2x + 3 = 0          
Factorise
(x + 1)(x - 3) = 0        <<< this is NOT the correct factorization of x^2-2x+3, rather is is the correct factorization of x^2-2x-3 
x + 1 = 0
x = -1
x - 3 = 0
x = 3 (Disregard as negative)    <<<  left over from before his edits (??)
x = 3 is the answer.        <<< yes, correct
Hope this helps :-)