Question 1172145
{{{2y=-3x+6}}}
{{{3x+2y=6}}}


Perpendicular to that would be  some equation {{{2x-3y=C}}} and your value C needs to use the required point  (-2,6), so, 


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{{{2x-3y=2(-2)-3*6}}}

{{{highlight(2x+3y=-22)}}}