Question 1172108
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Hint:


You'll use very similar steps found here
<a href = "https://socratic.org/questions/how-do-you-solve-arcsin-x-arcsin-2x-pi-3">https://socratic.org/questions/how-do-you-solve-arcsin-x-arcsin-2x-pi-3</a>
Though instead of {{{alpha+beta = pi/3}}}, you are considering {{{alpha-beta = pi/3}}}, where {{{alpha = arcsin(2x)}}} and {{{beta = arcsin(x)}}}


Caution: The link posted has an error in one of the steps. Specifically the step where it says this
<img width="50%" src = "https://i.imgur.com/4M7DlXC.png">
The {{{-4x^4}}} should be {{{""+4x^4}}} since {{{(-x^2)*(-4x^2) = 4x^4}}}. Once this error is corrected, it will lead to the correct answer for {{{alpha+beta = pi/3}}}. Keep this in mind when you apply your steps to get the answer you're after.
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