Question 1171946
A wire is 28 feet long. It is cut into three pieces.
a + b + c = 28
The longest piece is twice as long as the shortest piece
a = 2c
 and the remaining piece is four feet longer than the shortest piece.
b = c + 4
Replace a with 2c, and b with (c+4) in the first equation
2c + (c+4) + c = 28
4c = 28 - 4
4c = 24
c = 24/4
c = 6 ft is the shortest
:
Find the length of each piece
a = 2(6)
a = 12 ft is the longest
and
b = 6 + 4
b = 10 ft is the remaining piece
:
:
Check 12 + 10 + 6 = 28