Question 1171899

B. Solve the ff. problems.

The perimeter of a rectangle is 152 meters. The width is 22 meters less than the length. Find the length and the width.
<pre>With perimeter being 152 m, {{{matrix(1,5, "length (L)", "+", "width (W)", "=", 152/2)}}}
                                               {{{matrix(1,6, L + W, "=", 76, "---", eq, "(i)")}}}
                                W = L - 22, or L - W = 22 ------ eq (ii), since width is also 22 m less than the length
                                                  2L = 98 ------ Adding eqs (i) & (ii)
                                        Length or {{{highlight_green(matrix(1,6, L, "=", 98/2 , "=", 49, m))}}}
                                              49 + W = 76 ------- Substituting 49 for L in eq (i)
                                        Width, or {{{highlight_green(matrix(1,6, W, "=", 76 - 49, "=", 27, m))}}}