Question 1171861
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<pre>

Let x be the amount invested at 4% (in dollars).

Then the rest (4000-x) dollars are invested at 2.5%.


Then you write the total annual simple interest equation


    0.04*x + 0.025*(4000-x) = 148   dollars.


From the equation


    x = {{{(148 - 0.025*4000)/(0.04-0.025)}}} = 3200 dollars.


<U>Answer</U>.  $3200 invested at 4% and the rest  (4000-3200) = 800 dollars are invested at 2.5%.


<U>CHECK</U>.  0.04*3200 + 0.025*800 = 148 dollars, total annual interest.   ! Precisely correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.