Question 1171819
binomial ~(10,0.3)
average is 10*0.3=3
variance is 3*0.7=2.1
sd is sqrt(V)=1.45

prob of 3 is 10C3*0.3^3*0.7^7=0.2668
for 4 the same approach or binompdf(10,0.4,4)=0.2508
for 5 it is 0.1029
sum and answer is 0.6205