Question 1171828
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    3x + 2y = 120   (1)

    2x + 4y = 160   (2)



Divide eq(2) by 2 (both sides). Keep equation (1) as is.  You will get

    3x + 2y = 120   (1')

     x + 2y =  80   (2')


Now subtract eq(2') from eq(1').  You will get

    2x      = 120 - 80 = 40

     x =               = 40/2 = 20.


Then from equation (2'),  

    20 + 2y = 80

         2y = 80 - 20 = 60

          y            = 60/2 = 30.


<U>ANSWER</U>.   20 yards in the lace ribbon roll and 30 yards in the satin ribbon roll.
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Solved.