Question 16333
(2n + 1)/7   >=  (n + 4)/5
35[(2n+1)/7  >=  [(n+4)/5]
5(2n+1)      >=  7(n+4)
10n+5        >=  7n+28
10n-7n       >=  28-5
3n          >=   23
3n/3        >=   23/3
n           >=   7  2/3