Question 1171711
the half-interval iz z(0.95)*sqrt(p*(1-p)/n)
=1.645* sqrt (0.146*0.854)/288=0.0342
The 90%CI is (0.114, 0.178)

This assumes that 14.6% of 288 is an integer, which it almost is. The actual number is 42/288 but it gives the same result except at the thousandth place.