Question 1171659
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First question is about the leg of the right-angled triangle opposite to the given angle; the hypotenuse is given.


    So, use the sine  

        difference of altitudes = 160*sin(32°).    (1)




In the second question,  you are given the hypotenuse and the altitude difference.


    Again, you use the same formula, but in other form

        sin(a) = {{{difference_of_altitudes/140}}} = {{{100/140}}} = 0.714.



    So, now find the critical angles as arcsin(0.714).
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