Question 1171628
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The y intercept always occurs when x = 0


Plug in x = 0 to get,
y = -(x+a)*(x-b)^2*(x+c)


y = -(0+a)*(0-b)^2*(0+c)


y = -(a)*(-b)^2*(c)


y = -a*b^2*c


The y intercept is -a*b^2*c
The location of the y intercept as an (x,y) point is (0, -a*b^2*c)


Since a,b,c are positive this makes a*b^2*c to be positive as well.
This flips to -a*b^2*c being negative.


Visually this indicates the function curve crosses the y axis somewhere below the x axis.


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Answer:  The y intercept is -a*b^2*c and it's some negative number.

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