Question 1171571
 Simplify:{{{(10xy^2 - 5x^2)/(4x - 8y^2)}}}
Factor out common terms
{{{(5x(2y^2 - x))/(4(x - 2y^2))}}}
factor out -1 in the denominator, changes the signs, cancel (2y^2-x)
{{{(5x(2y^2 - x))/(-4(2y^2 - x))}}} = {{{(5x)/(-4)}}} = {{{-5/4}}}x