Question 1171539
<br>
The middle of the three integers is the average of all three.<br>
117/3 = 39<br>
The integers are 37, 39, and 41.<br>
If you need a formal algebraic solution....<br>
let x = middle integer
then x-2 = smallest
and x+2 = largest<br>
{{{(x-2)+(x)+(x-2) = 117}}}
{{{3x = 117}}}
{{{x = 117/3 = 39}}}<br>