Question 1171456
regroup the terms to get:
(x^2 - 6x) + (y^2 + 8y) - 11 = 0
complete the squares to get:
(x-3)^2 - 9 + (y+4)^2 - 16 - 11 = 0
combine like terms to get:
(x-3)^2 + (y+4)^2 -36 = 0
add 36 to both sides of the equation to get:
(x-3)^2 + (y+4)^2 = 36
that's your equation in standard form of a circle.
the center is at (3,-4) and the radius is equal to sqrt(36) = 6
here's the graph of both equations.


<img src = "http://theo.x10hosting.com/2020/120901.jpg" >


since they are identical, they make the same figure on the graph.