Question 1171405
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x for oranges' calories

y for strawberries' calories


    2x + 3y = 112    (1)

    3x + 4y = 165    (2)


Multiply first equation by 3 (both sides) and the second equation by 2. You will get


    6x + 9y = 336    (3)

    6x + 8y = 330    (4)


Subtract equation (4) from equation (5).  The terms "6x" will cancel each other
and you will get single equation for the unknown y only


          9y - 8y = 336 - 330

             y    = 6.


So, we have 6 calories for each strawberry.


Now substitute y= 6 into very first equation. You will get

    2x + 3*6 = 112

    2x       = 112 - 18 =   94

     x                  = 94/2 = 47.


<U>ANSWER</U>.  47 calories for each orange and 6 calories per strawberry.  


<U>CHECK</U>.  Make checking on your own by substituting the found values into the original equations.
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Solved.