Question 1171400
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            This problem has a simple,  short,  straightforward and elegant solution.


            With my magic lamp,  I will show it to you now.


            Watch attentively every my step.



<pre>
Let x be the first number.


Then the second number is 2x, according to the condition.


Then the third number is  (40-x-2x) = 40-3x.



The sum of the first two numbers is 2 more than the third number

    x + 2x = (40-3x) + 2



Solve this simple equation

    x + 2x + 3x = 40+2

        6x      = 42

         x      = 42/6 = 7.



<U>ANSWER</U>.  The first number is 7;  the second number is 2*7 = 14, and the third number is  40 - 7 - 14 = 19.
</pre>

Solved.


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It is how this problem &nbsp;SHOULD &nbsp;be treated, &nbsp;solved, explained and taught.


The problem is designed, intended and expected to be solved in this way.


Any other way is &nbsp;LAME.


I know it and know this way, &nbsp;because I have my magic lamp.


A miracle is the fact that the problem is solved using only one single unknown and one single equation.


It is intended to teach 6-th grade (7-th grade ?) students in this way.