Question 1171333
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The given equation is in vertex form,<br>
{{{(x-h)^2=(4p)(y-k)}}}<br>
where the vertex is (h,k) and p is the directed distance from the directrix to the vertex.<br>
With the given equation, then, you can see immediately that the vertex (h,k) is (-2,5) and 4p=-8 so p is -2.<br>
Since p is the directed distance from the directrix to the vertex, p=-2 means the directrix is 2 units ABOVE the vertex, because it is 2 units down from the directrix to the vertex.  So the directrix is at y=5+2=7.<br>