Question 1171261
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Hi May spent 1/6 of her money on a dress and 2 blouses. The dress costs as much as 3 blouses. 
She spends 3/4 of the remaining money on a watch. The watch costs $220.50 more than the dress. 
How much did she have at first. 
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            Ignore the post by @gosgarithmetic,  since his setup is  INCORRECT.




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Let x = How much she had at first (dollars).


She first spent 1/6 of her money - so,  {{{(5/6)x}}}  of her amount remained.


Taking into account that the dress costs as much as 3 blouses, we can write the system of equations in this form

    {{{(1/6)x}}} = 3B + 2B                (1)

    {{{(3/4)*(5/6)*x}}} = 3B + 220.50        (2)


Simplify

    {{{(1/6)x}}} = 5B                     (3)

    {{{(15/24)*x}}} = 3B + 220.50           (4)


Multiply equation (3) by 6 (both sides).  Multiply equation (4) by 24 (both sides).  You will get

    x = 30*B                         (5)

    15x = 72B + 5292                 (6)


From (5), substitute the expression for x into (6). You will get

    15*30*B = 72*B + 5292

    450*B - 72*B = 5292

    378*B = 5292

        B = 5292/378 = 14.


Then from (5) we get the <U>FINAL ANSWER</U>:  

    x = 30*14 = 420 dollars.


<U>ANSWER</U>.  She had originally  420 dollars.
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Solved.